Find the values of a and b if
3 + √2 / 3- √2 = a+b √2.
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3- √2 = a+b √2.
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LHS
3+√2/3-V2
= (3+√2)^2 /{3-√2}{3+√2}
= (9+2+6√2)/9-4
= (11+6√2)/5
= 11/5 + 6√2/5
On comparing LHS AND RHS we get,,
a=11/5
and,
b= 6/5
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