सिद्ध किजिए 3+अंडर रूट 5 एक अपरिमेय संख्या है
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सिद्ध किजिए 3+अंडर रूट 5 एक अपरिमेय संख्या है
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Answer:
you can take hint from here it's same like 3+√5 only
[tex]\huge\underline\mathfrak\color{red} Answer[/tex]
Let us assume that 6+√2 is rational.
That is , we can find coprimes a and b (b≠0) such that
6+√2 = a/b
√2= a/b - 6
[tex] \sqrt{2 - \frac{a - 6b}{b} } [/tex]
Since , a and b are integers , is rational ,and so √2 is rational.
But this contradicts the fact that √2 is irrational.
So, we conclude that 6+√2 is irrational.