A bucket is filled with water upto a height of 36 cm. How much a coin lying at its bottom appears to be raised when viewed from outside the water? [Refractive index of water = 4/3]
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A bucket is filled with water upto a height of 36 cm. How much a coin lying at its bottom appears to be raised when viewed from outside the water? [Refractive index of water = 4/3]
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To find: How much a coin lying at its bottom appears to be raised when viewed from outside the water?
Step-by-step-explanation:
Formula used:
Refractive index: [tex]\frac{D_{real} }{D_{apparent} }[/tex]
here
Refractive index of water: 4/3
Real depth = 36 cm
Apparent depth =?
Put the values
[tex]\frac{4}{3}=\frac{36}{D_{apparent} }[/tex]
Cross multiply to find apparent depth to find the coin depth
[tex]D_{apparent} =\frac{36x3}{4}[/tex]
[tex]D_{apparent} =27cm[/tex]
The coin raised up = Real depth-Apparent depth
=36-27
= 9 cm
Final answer:
The coin seems to be raised 9 cm up from the bottom when viewed from the outside.
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