Frame a quadratic polynomial whose sum of zeroes is -2/3 and product of zeroes is -3.
Guys if u give with proper steps i will mark as brainliest.
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Frame a quadratic polynomial whose sum of zeroes is -2/3 and product of zeroes is -3.
Guys if u give with proper steps i will mark as brainliest.
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Step-by-step explanation:
ATQ,
[tex] \alpha + \beta = - 2\3 [/tex]
and
[tex] alpha x beta = - 3[/tex]
so , the formula to make quadratic equations is ( when two of its zeroes are given) is x^2 - sx + p
(s = sum of zeroes ) , ( p=product of zeroes )
HOPE IT HELPS YOU ...!!
Verified answer
Step-by-step explanation:
The formula for forming a quadratic polynomial is
QP = K ( x2 - Sx + P) = 0
Where S stands for sum of zeroes and P stands for product of zeroes
Now just put the values
QP = K ( x2 - ( -2/3x ) + ( -3) ) = 0
Take LCM
QP = K ( 3x2 + 2x - 9 / 3 ) = 0
Both K and the denominator 3 transfers to LHS and gets multiplied by 0 , so the answer that we get is
QP = ( 3x2 + 2x - 9 )