The length of a rectangle is 10/3 cm more than its breadth. If its breadth is equal to the side of a square whose perimeter is 24 cm, then the area of rectangle in square cm will be
The length of a rectangle is 10/3 cm more than its breadth. If its breadth is equal to the side of a square whose perimeter is 24 cm, then the area of rectangle in square cm will be
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Answer:
let breadth of rectangle be xcm
it's length=10/3+x cm
a to q
side of square=breadth of rectangle==x cm
perimeter of square=24cm
4 *side=24
4x=24
x=6cm
breadth of rectangle=6cm
length of rectangle=10/3+6
=28/3cm
area of rectangle=length*breadth
area of rectangle=28/3*6
area of rectangle=56cm square
Answer:
The length of a rectangle is 10/3 cm more than its breadth. If its breadth is equal to the side of a square whose perimeter is 24 cm, then the area of rectangle in square cm will be
Let length of rectangle=lcm
breadth of rectangle= bcm
Given length is 3 times its breadth
i.e. l= 3×b
Perimeter of the rectangle= 120 cm
i.e.2×( l+ b)=120
2×(3×b+ b)=120
2×(4×b)=120
8×b=120
b= 15 cm