3. Find the area of the triangle whose sides are 42 cm, 34 cm and 20 cm in
length. Hence, find the height corresponding to the longest side.
trianglo whose sides are 18 m 24 cm and
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3. Find the area of the triangle whose sides are 42 cm, 34 cm and 20 cm in
length. Hence, find the height corresponding to the longest side.
trianglo whose sides are 18 m 24 cm and
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Step-by-step explanation:
Sides of the triangle are a=42,b=34,c=20
According to Hero's formula,
Area of the triangle, A=s(s−a)(s−b)(s−c)
Where s=2a+b+c=242+34+20=48
Now,
A=48(48−42)(48−34)(48−20)
A=48(6)(14)(28)
A=(6×8)(6)(14)(14×2)
A=14×6×4
A=336cm2
Let the height corresponding to longest side (42cm) is h
Area =21×base×height
21×42×h=336
h=42336×2=16 cm
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