solve for x, x-2/x-3 +x-4/x-5 = 10/3, x not equal to 3,5
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solve for x, x-2/x-3 +x-4/x-5 = 10/3, x not equal to 3,5
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Answer:
I am in 6th standard I don't know how to solve
x−3x−2+x−5x−4=310
⇒(x−3)(x−5)(x−2)(x−5)+(x−3)(x−4)=310
⇒x2−8x+15x2−7x+10+x2−7x+12=310
⇒x2−8x+152x2−14x+22=310
⇒3(2x2−14x+22)=10(x2−8x+15)
⇒6x2−42x+66=10x2−80x+150
⇒10x2−80