5x-1/3-2x-2/3=1
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[tex]\huge\tt\orange{answer:}[/tex]
[tex]\large\bf\color{navy} To \: solve : \\ \tt 5x - \frac{1}{3} - 2x - \frac{2}{3} = 1 \\ \\ \tt : \longrightarrow 3x - \frac{1}{3} - \frac{2}{3} = 1 \\ \\ \tt : \longrightarrow 3x - \frac{1 - 2}{3} = 1 \\ \\ \tt : \longrightarrow 3x - \frac{ - 1}{3} = 1 \\ \\ \tt : \longrightarrow \frac{9x - ( - 1)}{3} = 1 \\ \\ \tt : \longrightarrow \frac{9x + 1}{3} = 1 \\ \\ \tt : \longrightarrow 9x + 1 = 3 \\ \tt : \longrightarrow 9x = 3 - 1 \\ \tt : \longrightarrow 9x = 2 \\ \\ \tt : \longrightarrow x = \color{navy}{ \underline{ \boxed{ \tt \: \: \frac{2}{9} \: \: }}}[/tex]
[tex]\large\tt\orange{hope~it~helps..!!}[/tex]