32 x 10^5 dyne is applied on an stationary object of 40 kg. After 2 minutes what will be it's momentum.
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32 x 10^5 dyne is applied on an stationary object of 40 kg. After 2 minutes what will be it's momentum.
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1 dyne=10^-5 N
32*10^5 dyne=32 N
u=0
t=2*60
=120 sec
therefore
initial momentum=pi=0
also
F*t=pf-pi
F*t=pf
pf=32*120
=3840 kg m/s
Hope this helps