∫sinx /3+5cos x [integration class 12 ISC]
solve ?
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3+5cos x [integration class 12 ISC] solve ?
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Answer:
Integral (sinx/3+5cosx) dx
Put 3+5cos x = u
Differentiating both sides,
-5 sin x dx = du
which means,
sin x dx = -1/5 du
So, integral changes to
Integral (1/u)(-du/5) = -1/5 Integral du/u = -1/5 ln |u| + c
= -1/5 ln |3+5cos x | + c
Hope this helps you ! :)
Answer:
[tex] \huge{ \color{lime}- \frac15 \: \: \log |3+5cosx| +c }[/tex]
Step-by-step explanation:
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