3a + 4b +5c; when a- 1, b=0 and c-1
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Answer:
8
Step-by-step explanation:
substitute a= 1 b=0 c=1 in 3a+4b+5c
3×1+4×0+5×1
3+0+5
8
Verified answer
Answer:
a=-1,
b=0
c=-1
3a+4b+5c
=3×(-1)+4×0+5×(-1)
=-3+0-5
=-8