3m
b) A car having mass 700kg is moving at a speed of 90kmph. On applying brakes the speed is
reduced to 36kmph in 10 sec. Calculate
(i) the change in momentum
(ii) force applied by the brakes.
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3m
b) A car having mass 700kg is moving at a speed of 90kmph. On applying brakes the speed is
reduced to 36kmph in 10 sec. Calculate
(i) the change in momentum
(ii) force applied by the brakes.
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Answer:
p=37800N•s , F=3780N
Step-by-step explanation:
⚡ Formula to remember:-p=mv
⚡Formula to remember:- F=p/t
ANSWER
Given mass of car =1000kg
u=speed=90km/hr=90×
18
5
m/sec
u=25m/sec
it have to stop in 5sec
then final velocity =0
⇒v=u+at
o=25+a×5
=a=−5m/sec
2
then the force applied by break is ma
=1000X−(5m/sec
2
)
=−5000M
force =5000N by break
distance travelled to stop the car after break is applied (s=distance)
v
2
=u
2
+2as
0=(25)
2
−2×5×s
=s=
10
(25)
2
=62.5m
work done by break =F×s
w=5000×62.5=312.5KJ