1. Factorise: a² + 4b^2+c^2/9 + 4ab -4bc/3- 2ca/3
please give the right answer (。ŏ﹏ŏ)
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1. Factorise: a² + 4b^2+c^2/9 + 4ab -4bc/3- 2ca/3
please give the right answer (。ŏ﹏ŏ)
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Answer:
{a + (2b) - (c/3)}^2
Step-by-step explanation:
(a + b - c)² = a² + b² + c² + 2 (ab - bc - ca)
Answer:
Given expression is 9c−a
2
+4ab−4b
2
.
We can write it as:
9c−(a
2
−4ab+4b
2
)
Using the property (a−b)
2
=a
2
−2ab+b
2
, we can write a
2
−4ab+4b
2
as (a−2b)
2
Hence, the expression becomes,
9c−(a−2b)
2
⇒(3
c
)
2
−(a−2b)
2
Now, using the property a
2
−b
2
=(a+b)(a−b), the expression can be written as:
[3
c
+a−2b][3
c
−a+2b]
Hence, 9c−a
2
+4ab−4b
2
=[3
c
+a−2b][3
c
−a+2b].