1/5x+y+2=0
y=1/3x-10
(substituition method)
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3x-10 (substituition method)
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Step-by-step explanation:
multiply equation 1 and 2 by 5 and 3
x+5y+10=0
3y=x-30
put x =3y+30
3y+30+5y+10=0
8y=-40
y=-5
put y=-5 in any equation
we get x=15
Answer:
Step-by-step explanation:
Given:
[tex] \frac{1}{5}x + y + 2 = 0 \\ \: \: \: \: \: \: or \\ \frac{1}{5} x + y = - 2 = > \frac{x + 5y}{5} = - 2 \\ x + 5y = 5( - 2) = > x + 5y = - 10 \: \: \: \: \: ....(1) \\ \\ y = \frac{1}{3} x - 10 = > y = \frac{x - 30}{3} ....(2)[/tex]
putting value of y in eq.(1)
[tex] = > x + 5y = - 10 \\ = > x + 5 ( \frac{x - 30}{3}) = - 10 \\ = > x + \frac{5x - 150}{3} = - 10 \\ = > 3x + 5x - 150 = 3( - 10) \\ = > 8x = - 30 + 150 \\ = > 8x = 120 \\ = > x = \frac{120}{8} \\ x = > 15[/tex]
Now, putting value of x in eq.(2)
[tex] = > y = \frac{x - 30}{3} \\ = > 3(y) = 15 - 30 \\ = > 3y = - 15 \\ = > y = \frac{ - 15}{3} \\ y = > - 5[/tex]
Hence, the value of x is 15 and y is -5.