3x-1+2(x+1=5y+1+6y-1
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On putting x1=X and y1=Y in given equations, we get
3X+5Y=151⇒5X+3Y=1 ...(i)
2X+3Y=121⇒6X+4Y=1 ...(ii)
On multiplying (i) by 6 and (ii) by 5, we get
30X+18Y=6
−30X−+20Y=−5
−2Y=1
∴Y=−21
On putting Y=−21 in (i), we get
5X+3×−21=1⇒5X=25⇒X=21
∴x=X1
Step-by-step explanation:
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