find the expansion of (2x-1/3y)^3
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Answer:
(a-b)³ = a³-b³-3ab(a-b)
(2x-1/3y)³
=(2x-1)³/(3y)³
= [8x³-1-3(2x)(1)(2x-1)]/27y³
= (8x³-1-12x²+6x)/27y³
Step-by-step explanation:
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