The sum of the roots of the equation -x² + 3 x -3=0 is
A) 3
B) 3/4
C) -3
D) 1
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The sum of the roots of the equation -x² + 3 x -3=0 is
A) 3
B) 3/4
C) -3
D) 1
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GIVEN :-
TO FIND :-
SOLUTION :-
★ If the polynomial is x² + 3x - 3 = 0.
➠ x² + 3x - 3 = 0
As we know that,
➠ ɑ + β = -cofficient of x/cofficient of x²
➠ ɑ + β = -b/a
➠ ɑ + β = -3/1
➠ ɑ + β = -3
Hence the sum of the roots of the equation x² + 3x - 3 = 0 is -3.
★ If the polynomial is -x² + 3x - 3 = 0.
➠ -x² + 3x - 3 = 0
As we know that,
➠ ɑ + β = -cofficient of x/cofficient of x²
➠ ɑ + β = -b/a
➠ ɑ + β = -3/-1
➠ ɑ + β = 3
Hence the sum of the roots of the equation -x² + 3x - 3 = 0 is 3.
[tex] [/tex]
★═══════════════════★
➳ ɑ + β = -cofficient of x/cofficient of x²
➳ ɑ × β = constant term/cofficient of x².
➳ quadratic formula = [ { -b ± √( b² - 4ac ) }/2a ]
➳ quadratic equation = x² - (ɑ + β)x + (ɑβ) = 0
[tex]\large{\underline{\sf{\orange{Given-}}}}[/tex]
[tex]\large{\underline{\sf{\pink{To \: Find-}}}}[/tex]
[tex]\large{\underline{\sf{\purple{Solution-}}}}[/tex]
[tex]:\implies\sf\alpha + β = -cofficient of x/cofficient of x²[/tex]
[tex]:\implies\sf\alpha+ β = -b/a[/tex]
[tex]:\implies\sf\alpha+ β = -3/1[/tex]
[tex]:\implies\sf\alpha+ β = -3[/tex]
Hence the sum of the roots of the equation x² + 3x - 3 = 0 is -3.