4) Calculate the mass of
(b) 0.05 mole of Ammonia.
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4) Calculate the mass of
(b) 0.05 mole of Ammonia.
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Answer:
Ans= 0.85 gram
Explanation:
Ammonia= NH3
Mass of Nitrogen(N) = 14
Mass of Hydrogen (H)= 1
" " H3 = 3
: Mass Of 1 mole of NH3 =
Mass of N + Mass Of H3
14+1×3 = 17 gram
Mass of 1 mole of NH3 =17 gram
Mass of 0.05 mole of NH3
= 0.05× Mass of NH3
0.05×17=0.85 gram