rakesh runs at 5/4 of his usual speed and reaches the playground 5 min earlier . What is his usual time.. plzz help me and post the correct answer..
rakesh runs at 5/4 of his usual speed and reaches the playground 5 min earlier . What is his usual time.. plzz help me and post the correct answer..
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
then his final speed = 5x/4 ( because he is running at 5/4 of his usual speed )
initial speed : final speed = x : 5x/4 = 4 : 5 and then his time ratio = 5x/4 : x
He reached 5 min earlier so his new time minus initial time = 5x/4 - x = x/4
and x/4 = 5
so his new time will be 20 minutes and then his usual time will be 25 minutes ( because he reached 5 min earlier as given in the question so ans is 20 min + 5 min = 25 min )
Answer:
Step-by-step explanation:
Let Rakesh's initial speed = x
then his final speed = 5x/4 ( because he is running at 5/4 of his usual speed )
initial speed : final speed = x : 5x/4 = 4 : 5 and then his time ratio = 5x/4 : x
He reached 5 min earlier so his new time minus initial time = 5x/4 - x = x/4
and x/4 = 5
so his new time will be 20 minutes and then his usual time will be 25 minutes ( because he reached 5 min earlier as given in the question so ans is 20 min + 5 min = 25 min )