4. Product of two numbers is 6300 and their HCF is 15 find the smaller number
a)450
b)320
c)430
d)420
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4. Product of two numbers is 6300 and their HCF is 15 find the smaller number
a)450
b)320
c)430
d)420
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Answer:
Let the two numbers be x and y respectively.
It is given that the product of the two numbers is 6300, therefore,
xy=6300
Also 15 is their HCF, thus both numbers must be divisible by 15.
So, let x=15a and y=15b, then
Therefore, required possible pair of values of x and y which are prime to each other are (1,28) and (4,7).
Thus, the required numbers are (15,420) and (60,105).
Hence, the number of possible pairs is 2.