4. Two objects of masses 100 g and
200 g are moving along the same
line and direction with velocities
of 2ms and Imst respectively.
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4. Two objects of masses 100 g and
200 g are moving along the same
line and direction with velocities
of 2ms and Imst respectively.
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Before Collision After collision
A B A B
100 g 200g → 100g 200g
2m/s 1m/s v=? 1.67ms
−1
Let the 100 g and 200 g objects be A and B as shown in above figure.
Initial momentum of A=
1000
100
×2=0.2kgms
−1
Initial momentum of B=
1000
200
×1=0.2kgms
−1
∴ Total momentum of A and B before collision
=0.2+0.2=0.4kgms
−1
Let the velocity of A after collision =v
∴ Momentum of A after collision =
1000
100
×v=0.1v
Also, momentum of B after collision
=
1000
200
×1.67=0.334kgms
−1
∴ Total momentum of A and B after collision
=0.1×v+0.334
Using the law of conservation of momentum, momentum of A and B after collision = momentum of A and B before collision
0.1×v+0.334=0.4
0.1×v=0.4−0.334
⇒v=
0.1
0.066
=0.66ms
−1
Before Collision After collision
A B A B
100 g 200g → 100g 200g
2m/s 1m/s v=? 1.67m/s
Let the 100 g and 200 g objects be A and B as shown in above figure.
Initial momentum of A= 100 /1000 x 2 = 0.2kgm/s
Initial momentum of B= 200/1000 x 1 = 0.2kgm/s
∴ Total momentum of A and B before collision
=0.2+0.2=0.4kgm/s
Let the velocity of A after collision =v
∴ Momentum of A after collision = 100/1000 x v = 0.1v
Also, momentum of B after collision
200/1000 x 1.67 = 0.334kgm/s
∴ Total momentum of A and B after collision
=0.1×v+0.334
Using the law of conservation of momentum, momentum of A and B after collision = momentum of A and B before collision
0.1×v+0.334=0.4
0.1×v=0.4−0.334
⇒v= 0.066/0.1 = 0.66m/s