A 100 N force applied on a block of mass 50 kg produces a constant velocity of 5 m/min on rough surface. The force of friction exerted on the block will be
1/100N
2/200N
3/300N
4/400N
please give relevant answer with process.
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A 100 N force applied on a block of mass 50 kg produces a constant velocity of 5 m/min on rough surface. The force of friction exerted on the block will be
1/100N
2/200N
3/300N
4/400N
please give relevant answer with process.
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Given:
On a block of mass 50 kg,
force applied= 100 N and moves with constant velocity
To find:
Force of friction exerted on block = ?
Solution:
Refer attachment
When a force is applied forward, friction acts backward
As mentioned, block moves with constant velocity which indicates acceleration is zero
F - Fs = ma
100 - Fs = 50 × 0
Mass cannot be zero but on multiplication,
100 = Fs
Fs = 100 N
Required answer:
Thus, force of friction exerted on block is 100N
Basic points:
# Solve more such questions to get a good hold on it
Answer:
It is a very interesting real fact that Force has a value if and only if the force applied on any body is moving with an acceleration i.e the velocity should get increasing. If not Force is simply Zero.
Force = Mass X Acceleration
If Velocity is constant or not changing, then Acceleration is absolute 0
Resulting Force = Zero.
In this case, when the Applied force 100 N was acted on the box, initially the Net force had a value until the box accelerated to 5 m/min (motion) from 0 m/min (rest). Once the box attained the velocity of 5 m/min and became constant, the Net force became Zero.
So, Net Force = Applied Force - Frictional Force
As per above Explanation Net Force becomes 0 as the velocity becomes constant.
0 = Applied Force - Frictional Force
Applied Force = Frictional Force = 100 N
Explanation:
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