4a square_4b square + 4a +1 factorize it
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4a square_4b square + 4a +1 factorize it
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Rewrite 9b29b2 as (3b)2(3b)2.
−(3b)2+(2a+1)2-(3b)2+(2a+1)2
Reorder −(3b)2-(3b)2 and (2a+1)2(2a+1)2.
(2a+1)2−(3b)2(2a+1)2-(3b)2
Since both terms are perfect squares, factor using the difference of squaresformula, a2−b2=(a+b)(a−b)a2-b2=(a+b)(a-b) where a=2a+1a=2a+1 and b=3bb=3b.
(2a+1+3b)(2a+1−(3b))(2a+1+3b)(2a+1-(3b))
Multiply 33 by −1-1 to get −3-3.
(2a+1+3b)(2a+1−3b)
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