4.Let's write all the possible factors of these pairs of numbers. Then, find their H.C.F
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4.Let's write all the possible factors of these pairs of numbers. Then, find their H.C.F
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Explanation:
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Answer:
a) 6,8
6=2×3
8=2×2×2
H.C.F= 2
b)12,16
12=2×2×3
16=2×2×2×2
H.C.F=2×2
= 4
c)18,24
18= 2×3×3
24=2×2×2×3
H.C.F=2×3
= 6
d) 27,36
27= 3×3×3
36=2×2×3×3
H.C.F=3
e) 30,40
30=2×3×5
40=2×2×2×5
H.C.F=2×5
= 10
f)32,40
32=2×2×2×2×2
40=2×2×2×5
H.C.F=2×2×2
= 8
g)36,48
36=2×2×3×3
48=2×2×2×2×3
H.C.F= 2×2×3
=12
h)42,56
42=2×3×7
56=2×2×2×7
H.C.F= 2×7
= 14
Hope it is helpful!