(5×-3y-2)^2=(5×)^2+(3y)^2+(2)^2-
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(5×-3y-2)^2=(5×)^2+(3y)^2+(2)^2-
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Verified answer
Answer:
((5-3*y)/2)^2+((5-3*y)/2)*y-2*y^2-(10)=0
Step by step solution :
STEP
1
:
Equation at the end of step 1
(5-3y) (5-3y)
{——————}2+(——————•y))-2y2)-10 = 0
2 2
STEP
2
:
5 - 3y
Simplify ——————
2
Equation at the end of step
2
:
(5-3y) (5-3y)
{——————}2+(——————•y))-2y2)-10 = 0
2 2
STEP
3
:
Equation at the end of step 3
(5-3y) y•(5-3y)
{——————}2+————————)-2y2)-10 = 0
2 2
STEP
4
:
5 - 3y
Simplify ——————
2
Equation at the end of step
4
:
(5-3y) y•(5-3y)
(((——————2)+————————)-2y2)-10 = 0
2 2
STEP
5
:
Equation at the end of step
5
:
(5 - 3y)2 y • (5 - 3y)
((————————— + ————————————) - 2y2) - 10 = 0
22 2
STEP
6
:
6.1 Finding a Common Denominator The left 22
The right 2
The product of any two denominators can be used
as a common denominator.
Step-by-step explanation:
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Answer:
( 5x-3y-2)² = (5x)² + (3y)² + (2)²-
2(5x) (3y) +2 (3y)(2)- 2(2)(5x)
= 25x² + 9y² + 4 - 30xy+ 12y -20x