write the principal value of tan^-1(root 3) + sin^-1 (1/5) - cot^-1 (-root 3) +cos ^-1 (1/5)
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write the principal value of tan^-1(root 3) + sin^-1 (1/5) - cot^-1 (-root 3) +cos ^-1 (1/5)
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Step-by-step explanation:
tan−13−cot(−3)
∵tan3π=3 and cot(π−6π)=−3
tan−13=3π
and
cot−1(−3)=π−6π
tan−13−cot(−3) =3π−(π−6π)
=3π−π+6π=−2π