the denominator of a rational number is greater than its numerator by 3 if 3 is subtracted from the numerator and 2 is added to its denominator the new number becomes 1 / 5 find the original number
the denominator of a rational number is greater than its numerator by 3 if 3 is subtracted from the numerator and 2 is added to its denominator the new number becomes 1 / 5 find the original number
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Numerator be x
Denominator be (x +3)
Fraction = x/(x+3)
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According to the question,
Then,
I hope this will help you
-by ABHAY
denominator of the rational number = x + 7
Therefore, the rational number = x/x+7
It is given that if 3 is subtracted from the numerator and 2 is added to its denominator, then new number becomes 1/5.
Therefore, x-3/(x+7)+2 = 1/5
=> x-3/x+9 = 1/5
=> 5x - 15 = x+9
=> 5x-x = 9+15
=> 4x = 24
=> x = 24/4 = 6
Putting x = 6 in (1), we get
Required rational number = 6/6+7 = 6/13