5. In AABC, D and E are points on AB and AC
respectively such that DE || BC. If AE = 2 cm,
EC = 3 cm and BC = 10 cm, then DE is equal to 4
How??
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5. In AABC, D and E are points on AB and AC
respectively such that DE || BC. If AE = 2 cm,
EC = 3 cm and BC = 10 cm, then DE is equal to 4
How??
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Thus, DE divides the two sides AB and AC proportionally.
Thus,AD/AB = AE/AC
Thus, ∆ABC≈∆ADE
AB/AD = AC/AE = BC/DE [C.S.C.T]
Now,
AC/AE = BC/DE
→DE = AE × BC/AC
→DE = 2 × 10/5 [AC = (AE+EC)= 2+3=5]
→DE= 4cm