2. Anirban travelled 1/2 km on foot and 4hole 2/5 km by bus to reach his school, How far did he travel to
reach his school?
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2. Anirban travelled 1/2 km on foot and 4hole 2/5 km by bus to reach his school, How far did he travel to
reach his school?
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Step-by-step explanation:
Total distance covered by Anirban -
[tex] = \: \: \frac{1}{2} + 4\frac{2}{5} = \frac{1}{2} + \frac{22}{5} \\ \\ = \frac{1 \times 5}{2 \times 5} + \frac{22 \times 2}{5 \times 2} \\ \\ = \frac{5}{10} + \frac{44}{10} \\ \\ = \frac{49}{10} = 4\frac{9}{10} \: km[/tex]
Therefore, Anirban travel 4 whole 9/10 km
Answer:
Answer = 4.9km
Step-by-step explanation:
Distance covered by Anirban on foot = 1/2 km
Distance covered by bus = 22/5 km
Distance travelled to reach his school = 1/2+22/5
Then take L.C.M
L.C.M of 2 and 5 = 10
1/2×5/5+22/5×2/2
5/10+44/10
49/10
4.9km