5 l of 0.1 M solution of sodium carbonate contains.a) 53 g b) 106g c) 10.6 g d) 1.06 g
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5 l of 0.1 M solution of sodium carbonate contains.a) 53 g b) 106g c) 10.6 g d) 1.06 g
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Explanation:
M=moles/volume litter
moles=M×volume in litter
mass = moles ×molar mass
mass=M×volume in litter ×molar mass
use this formula you will get the answer
Answer:
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Explanation:
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