The sum of three numbers is 58. The second number is 3 times of 2/5 of the first number and the third number is 6 less than the first number. Find the three numbers.
Pls ans with explanation
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The sum of three numbers is 58. The second number is 3 times of 2/5 of the first number and the third number is 6 less than the first number. Find the three numbers.
Pls ans with explanation
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Answer:
First Number = 20
Second Number = 24
Third Number = 14
Step-by-step explanation:
Let the first number be 'x'
Let the second number be 'y'
Let the third number be 'z'
Since, second number = 3*2/5x
Therefore, y = 3*2/5x
Since, third number = x-6
Therefore, z = x-6
Since, x + y + z = 58
Therefore, x + (3*2/5x) + (x-6) = 58
x + (6/5x) + (x-6) = 58
x + (6/5x) + x = 58 + 6
(Making denominators same)
5x/5 + 6x/5 + 5x/5 = 64
16x/5 = 64
16x = 64*5
16x = 320
x = 320/16
Hence, x = 20
Therefore, First number = x = 20
Second number = (3*2/5) * 20 = 6/5*20 = 6*4 = 24
Third number = x-6 = 20-6 = 16
Hope you understand
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