(5 power 0 + 6 power -1) × 3 power 2.
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Answer:
(5⁰+6-¹)×3²
= (1+1/6)×9
=7/6×9
=21/2
Verified answer
(5⁰ + 6⁻¹) × 3²
To solve this we must apply laws of exponents. First we will apply these two laws of exponents for the brackets.
⇒ (5⁰ + 6⁻¹) × 3²
⇒ [tex](1+\dfrac{1}{6})\times 3^{2}[/tex]
Now we will find the LCM of the denominators in the fractions in the bracket. The LCM of 1 and 6 is 6 so using this value we will make the denominators equal.
⇒ [tex](1+\dfrac{1}{6})\times 3^{2}[/tex]
⇒ [tex](\dfrac{1\times 6 }{1\times 6 } +\dfrac{1}{6})\times 3^{2}[/tex]
⇒ [tex](\dfrac{6 }{6 } +\dfrac{1}{6})\times 3^{2}[/tex]
Now add the denominators to obtain the answer of the brackets.
⇒ [tex](\dfrac{6 }{6 } +\dfrac{1}{6})\times 3^{2}[/tex]
⇒ [tex]\frac{7 }{6 }\times 3^{2}[/tex]
Now we'll find the value of 3².
3² = 3×3 = 9
⇒ [tex]\dfrac{7 }{6 }\times 9[/tex]
⇒ [tex]\dfrac{7 }{6 \div 3 }\times 9\div 3[/tex]
⇒ [tex]\dfrac{7 }{2}\times 3[/tex]
⇒ [tex]\dfrac{21}{2}[/tex]
[tex]\bf \therefore (5^{0} + 6^{-1}) \times 3^{2} = \frac{21}{2}[/tex]
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