5 years ago father's age was 8 times of son's age.Product of their present age is 450.Find their present age.
5 years ago father's age was 8 times of son's age.Product of their present age is 450.Find their present age.
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Answer:
Let the age of father be x years and age of his son be ( 45 - x ) years,
Five years ago,
Age of father = ( x - 5 ) years
Age of his son = ( 45 - x - 5 ) years = ( 40 - x ) years
According to the question,
Product of their ages five years ago = 4 × father's age five years ago
=> ( x - 5 ) ( 40 - x ) = 4( x - 5 )
= > \cancel{(x - 5)}(40 - x) = 4 \cancel{(x - 5)}=>
(x−5)
(40−x)=4
(x−5)
=> 40 - x = 4
=> 40 - 4 = x
=> 36 = x
Hence,
Present age of father = x years = 36 years
Present age of his son = ( 45 - x ) = ( 45 - 36 ) = 9 years