50 g of magnesium on treatment 40 g of carbon dioxide gives magnesium oxide. In this amount of excess reagent taken is
(a) 8.5 g
(b) 6.37 g
(c) 5.5 g
(d) 7.5 g
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50 g of magnesium on treatment 40 g of carbon dioxide gives magnesium oxide. In this amount of excess reagent taken is
(a) 8.5 g
(b) 6.37 g
(c) 5.5 g
(d) 7.5 g
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Answer:
Option A (8.5) is the correct answer
Explanation:
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Answer:
Explanation:
Mg + [tex]CO_{2}[/tex] = MgO + C
multiplying by 2 to balance it
2Mg + [tex]CO_{2}[/tex] = 2MgO + C
50g 40g
27g 44g (weight)
44g [tex]CO_{2\\}[/tex] = 48G Mg
1G [tex]CO_{2}[/tex] = 48/44g Mg
40g [tex]CO_{2}[/tex] = 48/44 INTO 40
Approximate-43.63
Mg =50g
approximate = 7g Mg (extra)
∴(b) 6.37