50 liter of water containing Ca(HCO3)2 when converted into soft water required 22.2g of Ca(OH)2 . Calcultated the amount of Ca(HCO3)2 per liter of hand water.
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50 liter of water containing Ca(HCO3)2 when converted into soft water required 22.2g of Ca(OH)2 . Calcultated the amount of Ca(HCO3)2 per liter of hand water.
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Answer:
0.972 gram/litre
Explanation:
Let us first write the chemical equation for better understanding;
Ca(HCO3)2 + Ca(OH)2 == 2CaCO3 + 2H2O
Here we can see that one mole of each reactant is required to product 2 moles of each product produced.
Molar mass of Ca(HCO3)2 is 162 and molar mass of Ca(OH)2 is 74
Number of mole in 22.2 gram of Ca(OH)2 = 22.2 / 74 = 0.3
Hence we will require 0.3 moles of Ca(HCO3)2
Weight of 0.3 moles of Ca(HCO3)2 = 0.3 x 162 = 48.6 grams
So gram per litre of Ca(HCO3)2 = 48.6 / 50 = 0.972 gram/litre
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