50 liter of water containing Ca(HCO3)2 when converted into soft water required 22.2g of Ca(OH)2 . Calcultated the amount of Ca(HCO3)2 per liter of hand water.
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50 liter of water containing Ca(HCO3)2 when converted into soft water required 22.2g of Ca(OH)2 . Calcultated the amount of Ca(HCO3)2 per liter of hand water.
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50 liter of water containing Ca(HCO3)2 when converted into soft water required 22.2g of Ca(OH)2 . Calcultated the amount of Ca(HCO3)2 per liter of hand water.
Explanation:
Explanation:
We start by first writing the chemical equations
Ca(HCO3)2 + Ca(OH)2 == 2CaCO3 + 2H2O
We can deduce that one mole of each reactant will be required to produce 2 moles of each product
Molar mass of Ca(HCO3)2 will be 162 and molar mass of Ca(OH)2 will be 74
No. of mole in 22.2 gram of Ca(OH)2 = 22.2 / 74 = 0.3
∴ will require 0.3 moles of Ca(HCO3)2
Weight of 0.3 moles of Ca(HCO3)2 = 0.3 x 162 = 48.6 grams
Ans
∴ gram per litre of Ca(HCO3)2 = 48.6 / 50 = 0.972 gram/liter
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