50ml of 0.2M NaOH + 50 ml 0.1M H2SO4 find ph
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Hey, there!
Here's the answer to the question.
Normality = Molarity × n-factor.
and
number of equivalence = Normality × volume
➡️ n factor for NaOH is 1 and for H2SO4 is 2.
(Now, refer to the attachment)
Conclusion: Since, the number of equivalence of both acid and base is same, they completely react to form salt. For this, the solution becomes neutral, i.e., pH = 7
Hope that helps.
Thanks.