राघव ! माधव ! सीते ! ललिते !
विमानयानं रचयाम।
नीले गगने विपुले विमले
वायुविहारं करवाम ||१||
उन्नतवृक्षं तुझं भवनम्।
क्रान्त्वाकाशं खलु याम।
कृत्वा हिमवन्तं सोपानं
चन्दिरलोकं प्रविशाम ||२|| can someone plzz translate it for me
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राघव ! माधव ! सीते ! ललिते !
विमानयानं रचयाम।
नीले गगने विपुले विमले
वायुविहारं करवाम ||१||
उन्नतवृक्षं तुझं भवनम्।
क्रान्त्वाकाशं खलु याम।
कृत्वा हिमवन्तं सोपानं
चन्दिरलोकं प्रविशाम ||२|| can someone plzz translate it for me
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Answer:
Answer:
Given:
Given that the sum of Kamal Marks in Mathematics and English is 40
Had he got 3 marks more in Mathematics and 4 marks less in English . The product would be 360
To Find:
We have to find Kamal's marks in Mathematics and English
Solution:
Let Marks in English = y
Marks in Mathematics = x
\begin{lgathered}\\\end{lgathered}
We have been given that
\hookrightarrow \boxed{\sf{\pink{ Sum \: of \: Marks = 40 }}}↪
SumofMarks=40
\hookrightarrow \sf{ \: x + y = 40 }↪x+y=40
\hookrightarrow \sf{ \: y = ( 40 - x ) }↪y=(40−x) ---------- ( 1 )
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\underline{\large\mathfrak\orange{According \: to \: the \: Question}}
AccordingtotheQuestion
Had he got 3 marks more in Mathematics and 4 marks less in English the product would be 360
\implies \sf{( x + 3 ) ( y - 4 ) = 36}⟹(x+3)(y−4)=36
Using Equation ( 1 )
\implies \sf{ ( x + 3 ) ( 40 - x - 4 ) = 360}⟹(x+3)(40−x−4)=360
\implies \sf{( x + 3 )(36 - x) = 360}⟹(x+3)(36−x)=360
\implies \sf{36x - x^2 + 108 - 3x = 360}⟹36x−x
2
+108−3x=360
\implies \sf{33x - x^2 + 108 = 360 }⟹33x−x
2
+108=360
\implies \sf{ x^2 - 33x + 252 = 0 }⟹x
2
−33x+252=0
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Solving the Quadratic Equation using middle term spitting method
\implies \sf{ x^2 - 33x + 252 = 0 }⟹x
2
−33x+252=0
\implies \sf{ x^2 - 12x - 21x + 252 = 0 }⟹x
2
−12x−21x+252=0
\implies \sf{ x( x - 12 ) - 21( x - 12 ) = 0 }⟹x(x−12)−21(x−12)=0
\implies \sf{( x - 12 ) ( x - 21 ) = 0 }⟹(x−12)(x−21)=0
Either
\implies \sf{ x - 12 = 0 }⟹x−12=0
\implies \boxed{\sf{ x = 12 }}⟹
x=12
Or
\implies \sf{ x - 21 = 0 }⟹x−21=0
\implies \boxed{\sf{ x = 21 }}⟹
x=21
_______________________________
\underline{\large\mathfrak\orange{Finding \: the \: Values}}
FindingtheValues
When x = 12
\implies \sf{ y = 40 - 12}⟹y=40−12
\implies \sf{ y = 28}⟹y=28
When x = 21
\implies \sf{ y = 40 - 21 }⟹y=40−21
\implies \sf{ y = 19 }⟹y=19
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\huge\underline{\sf{\red{A}\orange{n}\green{s}\pink{w}\blue{e}\purple{r}}}
Answer
\large\boxed{\sf{\purple{Marks \: in \: Mathematics = 12 }}}
MarksinMathematics=12
\large\boxed{\sf{\purple{Marks \: in \: English = 28 }}}
MarksinEnglish=28
\large\sf{\green{O}\orange{R}}OR
\large\boxed{\sf{\red{Marks \: in \: Mathematics = 21 }}}
MarksinMathematics=21
\large\boxed{\sf{\red{Marks \ : in \: English = 19 }}}
Marks :inEnglish=19
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