5th question plzzzz someone help me to do it
Share
5th question plzzzz someone help me to do it
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Tan^3A / Sec^2A + Cot^3A / Cosec^2A
= (sin^3A/cos^3A) / (1 / Cos^2A) + (Cos^3A/Sin^3A) / (1 / Sin^2A)
= Sin^3A/CosA + Cos^3A/SinA
= (Sin^4A + Cos^4A) / SinA.CosA
= [ (Sin^2A + Cos^2A)^2 - 2Sin^2A.Cos^2A] / SinA.CosA
= ( 1- 2Sin^A.Cos^A)/ SinA.CosA
RHS = SecA CosecA - 2sinAcosA
= 1/CosA . 1/SinA - 2SinACosA
= (1 - Sin^2A.Cos^2A) / sinAcosA
Hence LHS = RHS