A sphere of mass m is held between two smooth inclined walls. For sin 37° = 3/5,
the normal reaction of the wall (2) is equal to :
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A sphere of mass m is held between two smooth inclined walls. For sin 37° = 3/5,
the normal reaction of the wall (2) is equal to :
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Given that,
Value of angle [tex]\sin 37^{\circ}=\dfrac{3}{5}[/tex]
We need to calculate the normal reaction of the wall
Using balance equation
[tex]\sum y=0[/tex]
[tex]N_{2}\sin16^{\circ}+mg=N_{2}\sin37^{\circ}[/tex]...(I)
[tex]\sum x=0[/tex]
[tex]N_{2}\cos16^{\circ}=N_{1}\cos37^{\circ}[/tex]....(II)
We need to calculate the value of N₁
Using equation (II)
[tex]N_{1}=\dfrac{N_{2}\cos16^{\circ}}{\cos37^{\circ}}[/tex]
Put the value of N₁ in equation (II)
[tex]N_{2}\cos16^{\circ}+mg=\dfrac{N_{2}\cos16^{\circ}}{\cos37^{\circ}}\sin37^{\circ}[/tex]
Put the value in the equation
[tex]N_{2}\times0.96+mg=N_{2}\times0.96\times0.75[/tex]
[tex]N_{2}=\dfrac{mg}{0.45}[/tex]
[tex]N_{2}=\dfrac{20mg}{9}[/tex]
Hence, The value of N₁ is [tex]\dfrac{20mg}{9}[/tex]