6) How many terms are there in GP 3, 6, 12, 24,
384:
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6) How many terms are there in GP 3, 6, 12, 24,
384:
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Answer:
Here a=3 and r=6/3=2. let the number of terms be n
Then,t=384=a*r^(n-1)=384=3*2^(n-1)=384=72^(n-1)=128=2^(7)