Chapter :- Laws of motion
A block of mass is placed on a surface with a vertical cross -section given y = x³/6 . If the cofficient of friction is 0.5 , the maximum height above the ground at which the can be placed without slipping is ?
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Explanation :- A block of mass m is placed on a surface with a vertical cross section , then
tan = dy/dx = d(x³/6)/dx = x²/2'
Now , putting the value of x in y = x³/6 , we get
when x = 1
when x = -1
so , the maximum height above the ground at which the block can be placed without slipping is 1/6m Answer
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