6. The sum of the digits of a two digit number is 9. The digit obtained by increasing the digit in ten's place by two is one eighth of the number. Find the number.
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6. The sum of the digits of a two digit number is 9. The digit obtained by increasing the digit in ten's place by two is one eighth of the number. Find the number.
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Step-by-step explanation:
5952457236
12345
17+ aao
Answer:
By using 1 variable:-
Let the digit at tens place be x
one's place be (9-x)
Orignal number=10(x)+9-x
=10x+9-x
=9x+9
According to question:-
Removing denominator
8x+16=9x+9
9x-8x=16-9
x=7
Ten's digit=7
One's digit=(9-x)
=9-7
=2
Orignal number=9(7)+9
=63+9
=72