63. Find the sum of all natural number between 100 and 200 which are divisible by 3.
Share
63. Find the sum of all natural number between 100 and 200 which are divisible by 3.
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Verified answer
first no. (a)= 102last no. ( l) = 198
difference (d) = 3
To find,
total no. between 100 and 200 which is divisible by 3
l= a+(n-1) d
198= 102+(n-1)3
198-102=(n-1)3
96=3n-3
96+3=3n
99=3n
n=99÷3
n=33
therefore total no. = 33
Now,
Sum =n/2(a+l)
= 33÷2(102+198)
= 33÷2×300
=33×100
=33000 Ans.
Answer:
The “sum” of all the multiples of 3 between the numbers “100 and 200” are 4950. Let the no. of terms be denoted as n. Hence, the “sum” of all the multiples of 3 between the numbers “100 and 200” are 4950.