6.3 g of crystalline oxalic acid present in 100 ml of solution find molarity and normality
6.3 g of crystalline oxalic acid present in 100 ml of solution find molarity and normality
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Answer:
0.4
Explanation:
M = given weight (g)/1000/ v (ml)
M = 4.9 / 98 × 1000
= 4 /20
= 0.2
N= M × n - factor
= 0.2 × 2 = 0.4 hope its help u......TC❤