65) Find the perimeter of a rectangle whose breadth is 9cm and diagonal is 41cm.
The diagonal of rhombus measure 50cm and 48cm. Find its perimeter
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65) Find the perimeter of a rectangle whose breadth is 9cm and diagonal is 41cm.
The diagonal of rhombus measure 50cm and 48cm. Find its perimeter
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Verified answer
Answer:
Question 1 -:
Perimeter of the rectangle = 98 cm
Question 2 -:
Perimeter of the Rhombus = 138.6 cm
Step-by-step explanation:
Given :
Question 1 -:
Breadth of the rectangle = 9 cm
Diagonal of the rectangle = 41 cm
Question 2 -:
Diagonal of the Rhombus = 50 cm and 48 cm
To find :
Question 1 -:
Perimeter of the rectangle
Question 2 -:
Perimeter of the Rhombus
Concept :
Question 1 -:
We have to first find the length of the rectangle .
Using the Pythagoras theorem to find the length -:
Let,
AB = Length
AD = Breadth
AC = Diagonal
After that to find the perimeter of the rectangle use this formula -:
Where,
P = Perimeter
L = Length
B = Breadth
Question 2 -:
We have to first find the side of the Rhombus .
Using Pythagoras theorem -:
Let ,
AB = Side of the Rhombus
AC = ½ of 50 cm
=> 25 cm = OA
BD = ½ of 48 cm
=> 24 cm = OB
After that to find the perimeter of the Rhombus use this formula -:
Where,
A = Area of the Rhombus
a = Side
Solution :
Question 1 -:
Length -:
Perimeter of the rectangle -:
So , the perimeter of the rectangle is 98 cm .
Question 2 -:
Side of the Rhombus -:
Perimeter of the Rhombus -:
So , the perimeter of the Rhombus is 138.6 cm (approx) .