66) Find the perimeter of a rectangle whose breadth is 9cm and diagonal is 41cm.
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66) Find the perimeter of a rectangle whose breadth is 9cm and diagonal is 41cm.
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Answer:
answer solved and attached in the attachment above
Step-by-step explanation:
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[ REFER TO THE ATTACHMENT ]
Here, is a rectangle ABCD in witch breadth and diagonal are given
As we know that
All angles of a rectangle are right angles i.e. 90°
So,
AC² = AB² + BC² [ Pythagoras theorem ]
Now,
→ AC² = AB² + BC²
→ (41)² = (9)² + BC²
→ BC² = (41)² - (9)²
→ BC² = 1681 - 81
→ BC² = 1600
→ BC = √1600
→ BC = 40cm
Therefore length of the rectangle BC = 40cm
As we know that
Perimeter of a rectangle = 2 (l + b)
Put the values in the formula
Now,
→ Perimeter of the rectangle = 2 (l + b)
→ Perimeter of the rectangle = 2 (40 + 9)
→ Perimeter of the rectangle = 2 × 49
→ Perimeter of the rectangle = 98cm
Hence, the perimeter of the rectangle is 98cm.