{(2/3)^2}^3 × (2/3)^-4 × 3^-1 × 1/6
help me plzzz.............
with explanation
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{(2/3)^2}^3 × (2/3)^-4 × 3^-1 × 1/6
help me plzzz.............
with explanation
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Answer:
2/81
Step-by-step explanation:
[(2/3)^2]^3:
Multiply the two powers together using exponent (power) rules:
(2/3)^(2x3) = (2/3)^6 = 64/729
(2/3)^-4:
Using the exponent (quotient) rules, when you flip the fraction, you can flip the sign of the exponent:
(2/3)^-4 = (3/2)^4 = 81/16
3^-1:
Use the exponent (quotient) rule again:
3^-1 = (1/3)^1 = 1/3
Then put it all together:
64/729 x 81/16 x 1/3 x 1/6
= 2/81