A closed cylindrical tank of radius 14m and height 8m is made from a sheet of metal. How much sheet of metal is required? ( take π = 22/7)
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A closed cylindrical tank of radius 14m and height 8m is made from a sheet of metal. How much sheet of metal is required? ( take π = 22/7)
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Answer :
S O L U T I O N :
Given,
To Find,
Explanation,
[ Note :- Total surface area of a cylindrical tank = Sheet of a metal is required. ]
We know that,
Total surface area of cylindrical tank = 2πr(r + h)
[ Put the values ]
=> TSA = 2 × 22/7 × 14 × (14 + 8)
=> TSA = 2 × 22 × 2 × (22)
=> TSA = 44 × 2 × (22)
=> TSA = 88 × 22
=> TSA = 1936 m²
.°. Total surface area of a cylindrical tank = Sheet of a metal is required.
=> Sheet of a metal is required is 1936 m².
Therefore,
1936 m² sheet of metal is required.
Given:-
⠀
To find:-
⠀
Solution:-
⠀
★ Formula used:-
[tex]\star{\boxed{\sf{\orange{TSA\: of\: cylindrical\: tank = 2\pi r( r + h)}}}}[/tex]
⠀
[tex]\large{\tt{\longmapsto{2 \times \dfrac{22}{7} \times 14(14 + 8)}}}[/tex]
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[tex]\large{\tt{\longmapsto{2 \times 22 \times 2 \times 22}}}[/tex]
⠀
[tex]\large{\tt{\longmapsto{44 \times 2 \times 22}}}[/tex]
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[tex]\large{\tt{\longmapsto{88 \times 22}}}[/tex]
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[tex]\boxed{\large{\tt{\longmapsto{\red{1936\: m^2}}}}}[/tex]
⠀
Hence, the total surface area of cylindrical tank is 1936 m².