In the given figure, OACBO represents a quadrant of a circle of radius 4.5 cm with centre 0. Then, the area of shaded portion is (take it = 22/7| А C D 3 B 4.5 cm
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In the given figure, OACBO represents a quadrant of a circle of radius 4.5 cm with centre 0. Then, the area of shaded portion is (take it = 22/7| А C D 3 B 4.5 cm
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the area of quadrant is 1/4 πr²
1/4 ×22/7×4.5×4.5 =15.91cm²
Now the area of triangle DOB =1/2 base ×hight
1/2×3×4.5=6.75 cm²
now the area of shaded region is 15.91-6.75=9.16cm²
option b ia correct